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Question: Air contains nearly \(20\% \) oxygen by volume. Calculate the theoretical volume of air which will b...

Air contains nearly 20%20\% oxygen by volume. Calculate the theoretical volume of air which will be required for the burning of 200m3200{m^3} acetylene gas completely . All volumes are measured under the same conditions of temperature and pressure.
1. 2500m32500{m^3}
2. 500m3500{m^3}
3. 5000m35000{m^3}
4. 3000m33000{m^3}

Explanation

Solution

The combustion reaction of acetylene with oxygen gives carbon dioxide and water. This reaction follows the law of constant proportions and hence using stoichiometry we can determine the amount of air required for the burning of acetylene completely.

Complete step by step answer:
Let us write down the combustion reaction for acetylene:
C2H2+52O22CO2+H2O{C_2}{H_2} + \dfrac{5}{2}{O_2} \to 2C{O_2} + {H_2}O

From the above balanced reaction we know that acetylene burns in presence of oxygen gas to give out carbon dioxide gas and water vapours.
So from this we know that 52\dfrac{5}{2} moles of oxygen gas reacts with 1 mole of acetylene.

or, 1 mL of acetylene gas reacts stoichiometrically with 52\dfrac{5}{2} mL of oxygen gas.
Hence, 200m3200{m^3} of acetylene gas will need = 5mL2×1mL×200m3\dfrac{{5mL}}{{2 \times 1mL}} \times 200{m^3} of oxygen gas.

Solving the above question, we get the value for the amount of oxygen gas required for the complete combustion of acetylene gas, which will be : 500m3500{m^3} .

It is given in the question, that we need air, which has one of its components as oxygen gas for the combustion of acetylene and not pure oxygen
So, we need to find the amount of air we will need which will give us 500m3500{m^3} of oxygen gas.

In the question, it is mentioned that the air has 20%20\% oxygen by volume.
this means that in 100mL100mL of air , 20mL20mL of it is oxygen
In other words, 20mL20mL of oxygen can be found in 100mL100mL of air
hence, 500m3500{m^3} of oxygen gas can be found in = 100×50020m3\dfrac{{100 \times 500}}{{20}}{m^3}

Solving the above equation we get the value of amount of air needed for the complete combustion if acetylene as 2500m32500{m^3}
Hence Option 1 is correct.

Note:
The percentage of air given in the question is in the form of volume by volume, this is a popular method for determining composition of gases .
Acetylene gas is used for welding purposes as it is capable of producing the hottest flame .