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Question: \(AgCl + NH_{ 4 }OH \rightarrow \) …………….. This question has multiple correct options. (A) \(NH_...

AgCl+NH4OHAgCl + NH_{ 4 }OH \rightarrow ……………..
This question has multiple correct options.
(A) NH4ClNH_{ 4 }Cl
(B) Ag(NH3)2ClAg(NH_{ 3 })_{ 2 }Cl
(C) H2OH_{ 2 }O
(D) AgCl

Explanation

Solution

Hint: One of the compounds formed in this reaction is a complex compound. You can easily identify that in the options. Also, NH4OHNH_{ 4 }OH can be written as a mixture of ammonia and water. Now try to answer it accordingly.

Complete step by step answer:

The reaction between AgCl and NH4OHNH_{ 4 }OH will result in the products of Ag(NH3)2+Ag(NH_{ 3 })_{ 2 }^{ + } and Cl{ Cl }^{ - } ions.
The reason is that basically when you have a container that has NH4OH in it, you basically don’t have ammonium ions NH4+NH_{ 4 }^{ + } and OH{ OH }^{ - } ions as we are used to, instead, you have NH3NH_{ 3 } and some water in there because ammonium hydroxide is not very stable to stay that way, that is why those NH3NH_{ 3 } molecules will react with AgCl to make a complex of Ag(NH3)2+Ag(NH_{ 3 })_{ 2 }^{ + } with some Cl{ Cl }^{ - } ions as products.
Hence, we can say Silver chloride reacts with ammonium hydroxide to produce diamminesilverchloride and water.
AgCl+2NH4OHAg(NH3)2Cl+2H2OAgCl + 2 NH_{ 4 }OH \rightarrow Ag(NH_{ 3 })_{ 2 }Cl + 2 H_{ 2 }O

Therefore, we can conclude that the correct answers to this question are options B and C.

Note: This is "silver diammine" and not "silver diamine". There are two of the letters "m". "Amine" refers to the NH2-NH_{ 2 } group. If it contains ammonia, then "ammine" has two m's.
Silver Ammonium Chloride - This is a complex compound and considered not to be a True salt. This is also not a very stable product, and it will revert back to initial reactants (AgCl) and ammonia will be given off as a gas.