Question
Question: \(AgCl + NH_{ 4 }OH \rightarrow \) …………….. This question has multiple correct options. (A) \(NH_...
AgCl+NH4OH→ ……………..
This question has multiple correct options.
(A) NH4Cl
(B) Ag(NH3)2Cl
(C) H2O
(D) AgCl
Solution
Hint: One of the compounds formed in this reaction is a complex compound. You can easily identify that in the options. Also, NH4OH can be written as a mixture of ammonia and water. Now try to answer it accordingly.
Complete step by step answer:
The reaction between AgCl and NH4OH will result in the products of Ag(NH3)2+ and Cl− ions.
The reason is that basically when you have a container that has NH4OH in it, you basically don’t have ammonium ions NH4+ and OH− ions as we are used to, instead, you have NH3 and some water in there because ammonium hydroxide is not very stable to stay that way, that is why those NH3 molecules will react with AgCl to make a complex of Ag(NH3)2+ with some Cl− ions as products.
Hence, we can say Silver chloride reacts with ammonium hydroxide to produce diamminesilverchloride and water.
AgCl+2NH4OH→Ag(NH3)2Cl+2H2O
Therefore, we can conclude that the correct answers to this question are options B and C.
Note: This is "silver diammine" and not "silver diamine". There are two of the letters "m". "Amine" refers to the −NH2 group. If it contains ammonia, then "ammine" has two m's.
Silver Ammonium Chloride - This is a complex compound and considered not to be a True salt. This is also not a very stable product, and it will revert back to initial reactants (AgCl) and ammonia will be given off as a gas.