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Chemistry Question on d block elements

AgClAgCl is dissolved in excess of each of NH3,KCNNH _{3}, KCN and Na2S2O3Na _{2} S _{2} O _{3}. The complex ions produced in each case are

A

[Ag(NH3)2]+,[Ag(CN)2]+\left[ Ag \left( NH _{3}\right)_{2}\right]^{+},\left[ Ag ( CN )_{2}\right]^{+} and [Ag(S2O3)2]3−\left[ Ag \left( S _{2} O _{3}\right)_{2}\right]^{3-}

B

[Ag(NH3)2]2+,[Ag(CN)2]3−\left[ Ag \left( NH _{3}\right)_{2}\right]^{2+},\left[ Ag ( CN )_{2}\right]^{3-} and [Ag(S2O3)2]2−\left[ Ag \left( S _{2} O _{3}\right)_{2}\right]^{2-}

C

[Ag(NH3)4]2+,[Ag(CN)2]3−\left[ Ag \left( NH _{3}\right)_{4}\right]^{2+},\left[ Ag ( CN )_{2}\right]^{3-} and [Ag2(S2O3)2]2−\left[ Ag _{2}\left( S _{2} O _{3}\right)_{2}\right]^{2-}

D

[Ag(NH3)2]+,[Ag(CN)2]−\left[ Ag \left( NH _{3}\right)_{2}\right]^{+},\left[ Ag ( CN )_{2}\right]^{-}and [Ag(S2O3)2]3−\left[ Ag \left( S _{2} O _{3}\right)_{2}\right]^{3-}

Answer

[Ag(NH3)2]+,[Ag(CN)2]−\left[ Ag \left( NH _{3}\right)_{2}\right]^{+},\left[ Ag ( CN )_{2}\right]^{-}and [Ag(S2O3)2]3−\left[ Ag \left( S _{2} O _{3}\right)_{2}\right]^{3-}

Explanation

Solution

AgCl+2NH3⟶[Ag(NH3)2]ClAgCl +2 NH _{3} \longrightarrow\left[ Ag \left( NH _{3}\right)_{2}\right] Cl
AgCl+KCN⟶K[Ag(CN)2]+K+[Ag(CN)2]−AgCl + KCN \longrightarrow K \left[ Ag ( CN )_{2}\right]+ K ^{+} \left[ Ag ( CN )_{2}\right]^{-}
or AgCl+Na2S2O3⟶[Ag(S2O3)2]3−AgCl + Na _{2} S _{2} O _{3} \longrightarrow\left[ Ag \left( S _{2} O _{3}\right)_{2}\right]^{3-}