Solveeit Logo

Question

Question: After two hours, one- sixteenth of the starting amount of a certain radioactive isotope remained und...

After two hours, one- sixteenth of the starting amount of a certain radioactive isotope remained undecayed. The half life of the isotope is.

A

15 minutes

B

30 minutes

C

45 minutes

D

1 hour

Answer

30 minutes

Explanation

Solution

NN0=(12)t/T(116)=(12)2/T(12)4=(12)2/T\frac{N}{N_{0}} = \left( \frac{1}{2} \right)^{t/T} \Rightarrow \left( \frac{1}{16} \right) = \left( \frac{1}{2} \right)^{2/T} \Rightarrow \left( \frac{1}{2} \right)^{4} = \left( \frac{1}{2} \right)^{2/T}

T=0.56muhour\Rightarrow T = 0.5\mspace{6mu} hour = 30 minutes.