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Question: After inserting \(n\) A.M.'s between 2 and 38, the sum of the resulting progression is 200. The valu...

After inserting nn A.M.'s between 2 and 38, the sum of the resulting progression is 200. The value of nn is.

A

10

B

8

C

9

D

None of these

Answer

8

Explanation

Solution

The resulting progression will have n+2n + 2 terms with 2 as the first term and 38 as the last term.

Therefore the sum of the progression

=n+22(2+38)=20(n+2)= \frac { n + 2 } { 2 } ( 2 + 38 ) = 20 ( n + 2 ).

By hypothesis, 20(n+2)=20020 ( n + 2 ) = 200 \Rightarrow n=8n = 8.