Question

After absorbring a slowly moving neutron of Mass mN (momentum $\approx$ 0) a nucleus of mass M breaks into two nuclei of masses $m_1$ and $5m_1$ ($6\, m_1 = M + mN$ ) respectively. If the de Broglic wavelength of the nucleus with mass $m_1$ is $\lambda$, the de Broglie wevelength of the nucleus will be:

• A. $5\,\lambda$
• B. $\lambda$\5
• C. $\lambda$
• D. $25\,\lambda$

Answer 1

Answer: (C)

$\lambda$

Answer 2

$P_i = 0$ $P_f = P_1 + P_2$ $P_i = P_f$ $0 = P_1 + P_2$ $(P_1 = -P_2)$ $\lambda_{1} = \frac{h}{P_{1}}$ $\lambda _{2} = \frac{h}{P_{2}}$ $\left|\lambda_{1}\right| = \left|\lambda_{2}\right|$ $\lambda _{1} = \lambda _{2} = \lambda.$