Question

Addition of sodium thiosulphate solution to a solution of silver nitrate gives $X$ as white precipitate, insoluble in water but soluble in excess thiosulphate solution to give $Y$. On boiling in water, $Y$ gives $Z . X, Y$ and $Z$ respectively are

• A. $Ag_2S_2O_3,\, Na_3[Ag(S_2O_3)_2], \,Ag_2S$
• B. $Ag_2SO_4, \, Na[Ag(S_2O_3)_2],\, Ag_2S_2$
• C. $Ag_2S_2O_3,\, Na_5[Ag(S_2O_3)_3], \, AgS$
• D. $Ag_2SO_3, \, Na_3[Ag(S_2O_3)_2],\, Ag_2O$

Answer 1

Answer: (A)

$Ag_2S_2O_3,\, Na_3[Ag(S_2O_3)_2], \,Ag_2S$

Answer 2

The sequence of reactions are

Hence, $X = Ag _{2} S _{2} O _{3}$
$Y = Na _{3}\left[ Ag \left( S _{2} O _{3}\right)_{2}\right] Z= Ag _{2} S$