Question

Addition of excess of AgNO3 to an aqueous solution of 1 mole of PdCl2. 4NH3 gives 2 moles of AgCl. The conductivity of this solution corresponds to

• A. 1 : 2 electrolyte
• B. 1 : 4 electrolyte
• C. 1 : 1 electrolyte
• D. 1 : 3 electrolyte

Answer 1

Answer: (A)

1 : 2 electrolyte

Answer 2

$\left[Pb\left(NH_{3}\right)_{4}\right]Cl_{2} \to\left[Pb\left(NH_{3}\right)_{4}\right]^{2+}+2cI^{-}$
$It\, is \,1 : 2\, i.e., AB_{2}$ type of electrolyte.