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Question: Activity of radioactive element decreased to one third of original activity R<sub>0</sub> in 9 years...

Activity of radioactive element decreased to one third of original activity R0 in 9 years. After further 9 years, its activity will be –

A

R0

B

23\frac{2}{3}R0

C

R0 / 9

D

R0 / 9

Answer

R0 / 9

Explanation

Solution

A.P1 =13\frac { 1 } { 3 }, t1 = 9 years, A.P2 = ?, t2 = 18 years

A.P2 = = (13)18/9\left( \frac { 1 } { 3 } \right) ^ { 18 / 9 } = (13)2\left( \frac { 1 } { 3 } \right) ^ { 2 }= 19\frac { 1 } { 9 }