Question

Activation energy of a chemical reaction can be determined by –

• A. Evaluating rate constants at two different temperatures
• B. Evaluating velocities of reaction at standard temperatures
• C. Evaluating rate constant at standard temperatures
• D. Changing concentration of reactants

Answer 1

Answer: (A)

Evaluating rate constants at two different temperatures

Answer 2

By 2.303 log$\frac{K_{2}}{K_{1}}$ = $\left\lbrack \frac{T_{2} - T_{1}}{T_{1}T_{2}} \right\rbrack$