Question

Acidified potassium permanganate solution oxidises oxalic acid. The spin-only magnetic moment of the manganese product formed from the above reaction is ______ B.M. (Nearest Integer)

Answer 1

$KMnO_4\text {(acidic-medium)} + H_2C_2O_4 → CO_2 + Mn^{2+}$

$Mn^{+2}$ has $5$ unpaired electrons
∴ Spin only magnetic moment
$= \sqrt {5(5+2)}$
$= \sqrt {5 \times 7}$
$= \sqrt {35}$
$≈ 5.92 \ B.M$
$≈ 6 \ B.M$

So, the answer is $6$.