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Question: Acetyl bromide reacts with excess of \(\mathrm { CH } _ { 3 } \mathrm { MgI }\) followed by treatmen...

Acetyl bromide reacts with excess of CH3MgI\mathrm { CH } _ { 3 } \mathrm { MgI } followed by treatment with a saturated solution of NH4Cl\mathrm { NH } _ { 4 } \mathrm { Cl } gives

A

2-methyl-2-propanol

B

Acetamide

C

Acetone

D

Acetyl iodide

Answer

2-methyl-2-propanol

Explanation

Solution