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Question: Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl...

Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives

A

Acetone

B

Acetamide

C

2-Methyl-2-propanol

D

Acetyl iodide

Answer

2-Methyl-2-propanol

Explanation

Solution

+ CH3MgI ⟶\longrightarrow

→NH4Cl\xrightarrow { \mathrm { NH } _ { 4 } \mathrm { Cl } }

2-Methyl-2-propanol