Question

Acetamide and ethylamine can be distinguished by reacting with

• A. dilute $HCl$ and heat
• B. $NaOH$ solution and heat
• C. acidified $KMnO_4$
• D. $Br_2$ water

Answer 1

Answer: (B)

$NaOH$ solution and heat

Answer 2

Acetamide in the presence of NaOH and heat changes to acetic acid while ethylamine does not undergo any reaction. $\underset{\text{Acetamide}}{ {CH3CONH2 }}$ ${-> CH3COOH + NH3 ?}$