Question

Acetaldoxime on reduction with $Na/{C_2}{H_5}OH$ gives:
A. $2 - propanol$
B. $ethyl\,a\min e$
C. $acetaldehyde$
D. $ethanol$

Answer 1

In order to this question, first we will write the exact reaction as per the question. and the product is on the basis of the reactant. We will discuss more about the correct products of the given reaction.

Complete answer:
As per the question, first we will write the balanced reaction-
$C{H_3} - CH = NOH\mathop \to \limits^{Na - {C_2}{H_5}OH} C{H_3}C{H_2}N{H_2} + {H_2}O$
In the upper reaction, Aldoxime and keto oxime on reduction with $LiAl{H_{4\,}}\,or\,Na - {C_2}{H_5}OH$ give ${1^\circ }$ amine or ethyl amine.
Ethylamine is widely used in the chemical industry and organic synthesis. Ethylamine is produced on a large scale by two processes. Most commonly ethanol and ammonia are combined in the presence of an oxide catalyst: In this reaction, ethylamine is co produced together with diethylamine and triethylamine.
Hence, the correct option is (B).

Note:
Ethylamine is an organic compound with the formula $C{H_3}C{H_2}N{H_2}$. This colourless gas has a strong ammonia -like odor. It is miscible with virtually all solvents. It is a nucleophilic base, as is typical for amines. Ethylamine is widely used in the chemical industry and organic synthesis.