Question
Question: Acetaldehyde reacts with \({\text{NaOH}}\) to form: A. .
Step 3: Abstraction of proton from water by the anion (I) to form aldol.
Option A is not correct as the given aldehyde structure contains hydroxy group in the alpha position and so it is not a betahydroxyaldehyde or aldol.
Option C is not correct as the given ketone structure contains hydroxy group in the alpha position and so it is not a betahydroxyketone or aldol.
Option D is not correct as the given aldehyde structure contains hydroxy group in the gamma position and so it is not a betahydroxyaldehyde or aldol.
Thus, option B is correct.
Note:
Aldehydes which do not have α - hydrogen atoms will not undergo aldol condensation reaction.
For example, formaldehyde does not contain any α - hydrogen atom. So there are no acidic hydrogens available for abstraction by bases and hence it cannot undergo an aldol reaction to give beta hydroxy aldehyde or aldol. Its structure is shown below.
Pivaldehyde also does not contain any α - hydrogen atom. So there are no acidic hydrogens available for abstraction by bases and hence it cannot undergo an aldol reaction to give aldol. Its structure is shown below.