Question

According to the first law of thermodynamics,$\Delta U$ = q + W. in special cases the statement can be expressed in different ways. Which of the following is not a correct expression?

• A. At constant temperature, q = - W
• B. When no work is doen:, $\Delta U$ = q
• C. In gaseous system:, $\Delta U$ = q + P$\Delta V$
• D. When work is done by the system:, $\Delta U$ = q + W

Answer 1

Answer: (D)

When work is done by the system:, $\Delta U$ = q + W

Answer 2

: When work is done by the system,$\Delta U = q - W.$