Question

According to special theory of relativity, the mass m of a particle moving with speed v is

(Where $m_{0}$is the rest mass and c is the speed of light)

• A. $m = m_{0}$
• B. $m = m_{0}\sqrt{1 - \frac{v^{2}}{c^{2}}}$
• C. $m = \frac{m_{0}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$
• D. $m = \left\lbrack m_{0}\sqrt{1 - \frac{v^{2}}{c^{2}} - 1} \right\rbrack$

Answer 1

Answer: (C)

$m = \frac{m_{0}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$

Answer 2

According to special theory of relativity, mass of a particle moving with speed v is given by

$m = \frac{m_{0}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$