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Question

Physics Question on kinetic theory

According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is:-

A

32R\frac{3}{2} R

B

72R\frac{7}{2} R

C

92R\frac{9}{2} R

D

52R\frac{5}{2} R

Answer

72R\frac{7}{2} R

Explanation

Solution

The correct answer is (B) : 72R\frac{7}{2} R
Diatomic gas molecules have three translational degree of freedom, two rotational degree of freedom & it is given that it has one vibrational mode so there are two additional degree of freedom corresponding to one vibrational mode, so total degree of freedom =7
Cv?=2fR?=27R?