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Question

Question: According to heisenberg uncertainty principle...

According to heisenberg uncertainty principle

A

E=mc2E = mc^{2}

B

Δx×Δp≥h4π\Delta x \times \Delta p \geq \frac{h}{4\pi}

C

λ=hp\lambda = \frac{h}{p}

D

Δx×Δp=h6π\Delta x \times \Delta p = \frac{h}{6\pi}

Answer

Δx×Δp≥h4π\Delta x \times \Delta p \geq \frac{h}{4\pi}

Explanation

Solution

According to uncertainty principle, the product of uncertainties of the position and momentum, is Δx×Δp≥h/4π\Delta x \times \Delta p \geq h/4\pi.