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Question: According to Bohr’s theory, the electronic energy of H – atom in Bohr’s orbit is given by...

According to Bohr’s theory, the electronic energy of H – atom in Bohr’s orbit is given by

A

En=−2.18×10−19×Z2n2E_{n} = - \frac{2.18 \times 10^{- 19} \times Z}{2n^{2}}J

B

En=−2.179×10−18×Z2n2JE_{n} = - \frac{2.179 \times 10^{- 18} \times Z^{2}}{n^{2}}J

C

En=−2.179×10−18×Z2n2JE_{n} = - \frac{2.179 \times 10^{- 18} \times Z}{2n^{2}}J

D

En=−2.18×10−21×Z2n2JE_{n} = - \frac{2.18 \times 10^{- 21} \times Z^{2}}{n^{2}}J

Answer

En=−2.179×10−18×Z2n2JE_{n} = - \frac{2.179 \times 10^{- 18} \times Z^{2}}{n^{2}}J

Explanation

Solution

: En=−2.179×10−18×Z2n2JE_{n} = - \frac{2.179 \times 10^{- 18} \times Z^{2}}{n^{2}}J [For H – atom, Z = 1]