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Question: According to Bohr’s theory the angular momentum of an electron in 5<sup>th</sup> orbit is....

According to Bohr’s theory the angular momentum of an electron in 5th orbit is.

A

10hπ\frac{10h}{\pi}

B

25hπ\frac{25h}{\pi}

C

1.5hπ\frac{1.5h}{\pi}

D

2.5hπ\frac{2.5h}{\pi}

Answer

2.5hπ\frac{2.5h}{\pi}

Explanation

Solution

: mvr=nh2π=5h2π=2.5hπmvr = \frac{nh}{2\pi} = \frac{5h}{2\pi} = \frac{2.5h}{\pi}