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Question

Physics Question on mechanical properties of fluid

According to Bernoulli's equation Pρg+h+12v2g=\frac{P}{\rho g}+h+\frac{1}{2} \frac{v^{2}}{g}= constant The terms A,BA, B and CC are generally called respectively :

A

gravitational head, pressure head and velocity head

B

gravity, gravitational head and velocity head

C

pressure head. gravitational head and velocity head

D

gravity, pressure and velocity head

Answer

pressure head. gravitational head and velocity head

Explanation

Solution

According to Bernoulli's theorem, in case of steady flow of incompressible and non-viscous liquid through a tube of non-uniform cross-section, the sum of the pressure, the potential energy per unit volume and the kinetic energy per unit volume is same at every point in the tube, i.e., P+ρgh+12ρv2=P+\rho g h+\frac{1}{2} \rho v^{2}= constant Dividing this expression by ρg\rho g, we have Pρg+v22g+h=\frac{P}{\rho g}+\frac{v^{2}}{2 g}+h= constant In this expression Pρg\frac{P}{\rho g} is called the 'pressure head', v22g\frac{v^{2}}{2 g} the 'velocity head' and hh the 'gravitational head'.