Question

Acceleration due to gravity is $g$ on the surface of the earth. Then the value of the acceleration due to gravity at a height of $32\, km$ above earths surface is: (Assume radius of earth to be 6400 km)

• A. 0.99 g
• B. 0.8 g
• C. 1.01 g
• D. 0.9 g

Answer 1

Answer: (A)

0.99 g

Answer 2

$g=\frac{g}{{{\left( 1+\frac{h}{{{R}_{e}}} \right)}^{2}}}=\frac{g}{{{\left( 1+\frac{32}{6400} \right)}^{2}}}=0.99\,g$