Question

Acceleration due to gravity at earth's surface is 10 ms^–2. The value of acceleration due to gravity at the surface of a planet of mass $\frac{1}{5}th$ and radius $\frac{1}{2}$ of the earth is –

• A. 4 ms^–2
• B. 6 ms^–2
• C. 8 ms^–2
• D. 12 ms^–2

Answer 1

Answer: (C)

8 ms^–2

Answer 2

g_p = $\frac{GM_{p}}{R_{P}^{2}}$

= G × $\frac{1}{5}$ × Me × $\frac{4}{R_{e}^{2}}$

= $\frac{4}{5}$ g = 8 ms^–2