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Question

Physics Question on Gravitation

Abody of mass m is raised through a distance equal to the radius of the earth, (R), from the earth surface. Increase in potential energy is

A

mgRmgR

B

2mgR2 mgR

C

mgR2\frac{mgR}{2}

D

3mgR3 mgR

Answer

mgR2\frac{mgR}{2}

Explanation

Solution

Potential energy of mass mm on the surface of the earth, U1=mgRU_1 = -mgR.
Potential energy of mass mm at a distance RR above the surface of the earth, U1=mg(2R)U_1= -mg'(2R)
Here, g=GM(R+R)2=g4g' = \frac{GM}{\left(R +R\right)^{2}} = \frac{g}{4}
Uf=mgR2\therefore\:\: U_{f} =-\frac{mgR}{2}
Increase in potential energy of mass, m
=UfUi=mgR2+mgR=mgR2=U_{f} - U_{i} = - \frac{mgR}{2}+ mgR = mgR 2