ABCD is a rhombus, whose diagonals integralersect at E. Then... | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

ABCD is a rhombus, whose diagonals intersect at E. Then $\overrightarrow{EA}+\overrightarrow{EB}+\overrightarrow{EC}+\overrightarrow{ED}$ equals to :

A

$\overrightarrow{0}$

B

$\overrightarrow{AD}$

C

$2\overrightarrow{BC}$

D

$2\overrightarrow{AD}$

Answer

$\overrightarrow{0}$

Explanation

Solution

The correct option is (A) : $\overrightarrow{0}$ .