Question
Mathematics Question on Similarity of Triangles
△ABC∼△PQR; PQAB=QRBC=PRAC=k, then k value
A
k=1
B
k>1
C
k<0
D
k=0
Answer
k=1
Explanation
Solution
The correct option is (A): k=1.
△ABC∼△PQR; PQAB=QRBC=PRAC=k, then k value
k=1
k>1
k<0
k=0
k=1
The correct option is (A): k=1.