Question

$ABC$ is right angled triangular plane of uniform thickness. The sides are such that $AB>BC$ as shown in figure. $l_1, l_2, l_3$ are moment of inertia about $AB, BC$ and $AC$, respectively. Then which of the following relations is correct?

• A. $l_1=l_2=l_3$
• B. $l_2>l_1>l_3$
• C. $l_3<l_2<l_1$
• D. $l_3>l_1>l_2$

Answer 1

Answer: (B)

$l_2>l_1>l_3$

Answer 2

The correct option is (B): $l_2>l_1>l_3$.