Question

ABC is a triangle whose medians AD and BE are perpendicular to each other. If AD = p and BE = q then area

of ∆ABC is-

• A. $\frac{2}{3}pq$
• B. $\frac{3}{2}pq$
• C. $\frac{4}{3}pq$
• D. $\frac{3}{4}pq$

Answer 1

Answer: (A)

$\frac{2}{3}pq$

Answer 2

AM = $\frac{2}{3}p$, MD = $\frac{1}{3}p$, BM = $\frac{2}{3}q$

BM² = BM² + DM²