Question: ABC is a right angle triangle in which AB = 3 cm, BC = 4 cm and $\angle ABC = \frac{\pi}{2}$. The ...

Question

ABC is a right angle triangle in which AB = 3 cm, BC = 4 cm and $\angle ABC = \frac{\pi}{2}$ . The three charges +15, +12 and – 20 e.s.u. are placed respectively on A, B and C. The force acting on B is

Answer 1

Solution

Net force on B $F_{net} = \sqrt{F_{A}^{2} + F_{C}^{2}}$

$F _ { A } = \frac { 15 \times 12 } { ( 3 ) ^ { 2 } } = 20$ dyne $F_{C} = \frac{12 \times 20}{(4)^{2}} = 15dyne$

$F_{net} = 25dyne$

Question: ABC is a right angle triangle in which AB = 3 cm, BC = 4 cm and \(\angle ABC = \frac{\pi}{2}\). The ...

Solution