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Question: AB is a polar molecule. It's bond length is 5 Å. If the maximum dipole moment of the molecule is b x...

AB is a polar molecule. It's bond length is 5 Å. If the maximum dipole moment of the molecule is b x 10−2910^{-29} coulomb meter, what is the value of 'b'? [charge of e = 1.602 x 10−1910^{-19} C]

Answer

8.010

Explanation

Solution

The maximum dipole moment of a diatomic molecule AB with bond length d is calculated assuming a 100% ionic bond, where the charge separation is equal to the elementary charge e. The dipole moment is the product of this charge and the bond length. Convert bond length from Å to m. Calculate μmax=e×d\mu_{max} = e \times d. Compare the result with the given format b×10−29b \times 10^{-29} C m to find b.