Question

AB is a diameter of a circle. CD is a chord parallel to AB(as shown in the diagram) and 2CD = AB. The tangent at B meets the line AD produced at E, then –

• A. AE = 2AB
• B. $\sqrt{3}$AB = AE
• C. $\sqrt{2}$AB = AE
• D. 2AB = $\sqrt{3}$AE

Answer 1

Answer: (D)

2AB = $\sqrt{3}$AE

Answer 2

cos 30⁰ = $\frac{AB}{AE}$ = $\frac{\sqrt{3}}{2}$ Ž 2AB = $\sqrt{3}$AE