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Question: AB, AC are tangents to a parabola y<sup>2</sup> = 4ax. If l<sub>1</sub>, , l<sub>3</sub> are the len...

AB, AC are tangents to a parabola y2 = 4ax. If l1, , l3 are the lengths of perpendiculars from A, B, C on any tangent to the parabola, then –

A

l1, , l3 are in G.P.

B

, l1, l3 are in G.P.

C

l1, l3, are in G.P.

D

l3, , l1 are in G.P.

Answer

, l1, l3 are in G.P.

Explanation

Solution

Let the coordinates of B and C be (at12, 2at1) and (at22, 2at2) respectively. Then, the coordinates of A are (at­1t2 , a(t1 + t2)).

The equation of any tangent to y2 = 4ax is

ty = x + at2

\ l1 = at1t2a(t1+t2)t+at21+t2\frac{at_{1}t_{2} - a(t_{1} + t_{2})t + at^{2}}{\sqrt{1 + t^{2}}},

l2 = at122att1+at21+t2\frac{at_{1}^{2} - 2att_{1} + at^{2}}{\sqrt{1 + t^{2}}}

and l3 = at122att2+at21+t2\frac{at_{1}^{2} - 2att_{2} + at^{2}}{\sqrt{1 + t^{2}}}

Clearly, l 2 l 3 = l12. Therefore, l 2, l 1, l 3 are in G.P.

Hence (2) is the correct answer.