Question

A120 V, 60Hz a.c. power is connected $800\Omega$ non-inductive resistance and unknown capcitance in series. The voltage drop across the resistance is found to be 102V, then voltage drop across eapacitor is

• A. 8V
• B. 102V
• C. 63V
• D. 55V

Answer 1

Answer: (C)

63V

Answer 2

$V^2=V^2_c:V^2_c=V^2-V^2_R$ $V_c^2=(120)^2-(120)^2;V_c=63V$