Question
Physics Question on Electric Field
A Zener diode has a contact potential of 1V in the absence of biasing. It undergoes Zener breakdown for an electric field of 106V/m at the depletion region of p−n junction. If the width of the depletion region is 2.5μm, what should be the reverse biased potential for the Zener breakdown to occur?
A
3.5 V
B
2.5 V
C
1.5 V
D
0.5 V
Answer
2.5 V
Explanation
Solution
Reverse biased potential for the zener breakdown Vr=Ed =106×2.5×10−6 =2.5 volt