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Physics Question on Current electricity

A wire X of length 50 cm carrying a current of 2 A is placed parallel to a long wire Y of length 5 m. The wire Y carries a current of 3 A. The distance between two wires is 5 cm and currents flow in the same direction. The force acting on the wire Y is

A wire X of length 50 cm carrying a current of 2 A is placed parallel to a long wire Y of length 5 m

A

1.2 × 10–5 N directed towards wire X

B

1.2 × 10–4 N directed away from wire X

C

1.2 × 10–4 N directed towards wire X

D

2.4 × 10–5 N directed towards wire X

Answer

1.2 × 10–5 N directed towards wire X

Explanation

Solution

FXY = FYX = F
F=μ0I22πrI1(l)F=\frac{μ_0I_2}{2πr}I_1(l)
=4π×10−7×3×2×[50×10−2]2π(5×10−2)=\frac{4π×10^{−7}×3×2×[50×10^{−2}]}{2π(5×10^{−2})}
= 1.2 × 10–5 N
So, the correct option is (A): 1.2 × 10–5 N directed towards wire X