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Question: A wire stretches by a certain amount under a load. If the load and radius both are increased to four...

A wire stretches by a certain amount under a load. If the load and radius both are increased to four times. The stretch caused in the wire is

A

l

B

l2\frac{l}{2}

C

l3\frac{l}{3}

D

l4\frac{l}{4}

Answer

l4\frac{l}{4}

Explanation

Solution

: Young’s modulus, Y=WA×LlY = \frac{W}{A} \times \frac{L}{l}

Elongation,l=WLAY=WLπr2Y\therefore Elongation,l = \frac{WL}{AY} = \frac{WL}{\pi r^{2}Y}

When both load and radius are increased to four times, the elongation becomes

l=4W×Lπ(4r)2×Y=WL4πr2Y=l4l' = \frac{4W \times L}{\pi(4r)^{2} \times Y} = \frac{WL}{4\pi r^{2}Y} = \frac{l}{4}