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Question

Physics Question on Resistance

A wire of resistance RR and length LL is cut into 5 equal parts. If these parts are joined in parallel, then the resultant resistance will be:

A

5 R

B

25 R

C

R25\frac{R}{25}

D

R5\frac{R}{5}

Answer

R25\frac{R}{25}

Explanation

Solution

Each part will have resistance:

R=R5R' = \frac{R}{5}

When connected in parallel, the total resistance ReqR_{eq} is:

1Req=5×1R=5×1R/5=5×5R=1R/25\frac{1}{R_{eq}} = 5 \times \frac{1}{R'} = 5 \times \frac{1}{R/5} = 5 \times \frac{5}{R} = \frac{1}{R/25}

Thus,

Req=R25R_{eq} = \frac{R}{25}