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Question

Physics Question on Current electricity

A wire of resistance 1212 ohms per meter is bent to form a complete circle of radius 10cm10 \,cm. The resistance between its two diametrically opposite points, AA and BB as shown in the figure is

A

3Ω3\,\Omega

B

6πΩ6\pi \,\Omega

C

6Ω6\,\Omega

D

0.6πΩ0.6 \pi\,\Omega

Answer

0.6πΩ0.6 \pi\,\Omega

Explanation

Solution

Total resistance of wire =12Ω×2π×101=12\, \Omega \times 2 \pi \times 10^{-1}
=2.4π=2.4 \pi
Resistance of each half =2.4π2=1.2π=\frac{2.4 \pi}{2}=1.2 \pi
and as about diameter both parts are in parallel
Re =1.2π2=0.6πΩ=\frac{1.2 \pi}{2}=0.6\, \pi \Omega