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Question

Physics Question on Moving charges and magnetism

A wire of length LL is bent in the form of a circular coil of some turns. A current II flows through the coil. The coil is placed in a uniform magnetic field BB. The maximum torque on the coil can be

A

IBL22π\frac{IBL^{2}}{2\pi}

B

IBL24π\frac{IBL^{2}}{4\pi}

C

IBL2π\frac{IBL^{2}}{\pi}

D

2IBL2π\frac{2IBL^{2}}{\pi}

Answer

IBL24π\frac{IBL^{2}}{4\pi}

Explanation

Solution

Let rr be the radius of the coil and nn be the number of turns formed. Then
L=2πrnL = 2 \pi r n or r=L2πnr = \frac{L}{2 \pi n} ....(i)
Maximum torque, τmax=BnIA=BnIπr2\tau_{max} = B \, n\, IA = B \, n \, I \, \pi r^2
=BnIπ×L24π2n2=BIL24πn= B\, n \, I \, \pi \times \frac{L^2}{4 \pi^2 n^2} = \frac{B IL^2}{4 \pi n}
Torque will be maximum if n=1n = 1
τmax=BIL24π\therefore \:\:\:\:\: \tau_{max} = \frac{B I\, L^2}{4 \pi}