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Physics Question on Stress and Strain

A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to L1L_1 when mass M is suspended from its free end. The expression for Young’s modulus is:

A

MgL1AL\frac {MgL_1}{AL}

B

Mg(L1−L)AL\frac {Mg(L_1-L)}{AL}

C

MgLAL1\frac {MgL}{AL_1}

D

MgLA(L1−L)\frac {MgL}{A(L_1-L)}

Answer

MgLA(L1−L)\frac {MgL}{A(L_1-L)}

Explanation

Solution

Answer is option (D): MgLA(L1−L)\frac {MgL}{A(L_1-L)}