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Question

Physics Question on Gravitation

A wire of length ll and mass m is bent in the form of a semicircle. The gravitational field intensity at the centre of semicircle is

A

Gmπl\frac{Gm}{\pi{l}}along x-axis

B

Gmπl\frac{Gm}{\pi{l}}along y-axis

C

2πGml2\frac{2\pi Gm}{l^{2}}along y-axis

D

2πGml2\frac{2\pi Gm}{l^{2}}along x-axis

Answer

2πGml2\frac{2\pi Gm}{l^{2}}along y-axis

Explanation

Solution

Consider two small elements each of length dl=rdθd l=r d \theta symmetrically. πr=1\pi_{r}=1 Resolve the elemental field intensities dE1=dE2\because\left|d E_{1}\right|=\left|d E_{2}\right|