Question

A wire of length 314 cm carrying current of 14 A is bent to form a circle. The magnetic moment of the coil is _______ A–m2. [Given $\pi = 3.14$]

Answer 1

$R = \frac{I}{2\pi}$
$\frac{314}{2 \times 3.14}$
$=50 cm$
The magnetic moment of the coil,
$\mu = \pi R^2 i$
$14 \times 3.14 \times (0.5)^2$
$= 11$ A-m2
So, the answer is 11.