Question

A wire of density $8 × 10^3$ $kg/m^3$ is stretched between two clamps 0.5 m apart. The extension developed in the wire is $3.2 × 10^{–4}$ m. If Y = $8 × 10^{10}$ $N/m^2$ , the fundamental frequency of vibration in the wire will be ________Hz.

Answer 1

The Answer is : 80