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Question: A wire is suspended by one end. At the other end a weight equivalent to 20 *N* force is applied. The...

A wire is suspended by one end. At the other end a weight equivalent to 20 N force is applied. The ratio of the increase in energy of the wire to the decrease in gravitational potential energy when load moves downwards by 1 mm, will be

A

1

B

14\frac { 1 } { 4 }

C

13\frac { 1 } { 3 }

D

12\frac { 1 } { 2 }

Answer

12\frac { 1 } { 2 }

Explanation

Solution

Ratio of work done

= 1/2FlFl=12\frac { 1 / 2 F l } { F l } = \frac { 1 } { 2 }