Question

A wire is suspended by one end. At the other end a weight equivalent to 20 N force is applied. If the increase in length is 1 mm, the increase in the energy of the wire will be

• A. 0.01 J
• B. 0.02 J
• C. 0.04 J
• D. 1.00 J

Answer 1

Answer: (A)

0.01 J

Answer 2

Increase in energy $=\frac{1}{2}\times2\times1\times10^{-3}$
= 0.01 J