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Question: A wire is parallel to a square coil. The coil and wire carries currents in the directions shown. The...

A wire is parallel to a square coil. The coil and wire carries currents in the directions shown. Then, at any point A within the coil the magnetic field will be-

A

Less than the magnetic field produced due to coil only

B

More than the magnetic field produced due to coil only

C

Equal to the field by coil alone

D

Zero

Answer

More than the magnetic field produced due to coil only

Explanation

Solution

 B due to wire is B due to loop is }Bnet =Bwire +Bcoil \left. \begin{array} { l } \text { B due to wire is } \otimes \\ \mathrm { B } \text { due to loop is } \otimes \end{array} \right\} \Rightarrow \mathrm { B } _ { \text {net } } = \mathrm { B } _ { \text {wire } } + \mathrm { B } _ { \text {coil } }

Ž Bnet is more than Bcoil.