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Question: A wire is of mass (0.3 ± .003) gm. The radius is (0.5 ± 0.005) cm and length is (6 ± .06) cm. The ma...

A wire is of mass (0.3 ± .003) gm. The radius is (0.5 ± 0.005) cm and length is (6 ± .06) cm. The maximum percentage error in density is –

A

3%

B

4%

C

8%

D

16%

Explanation

Solution

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Sol. p = mπr2l\frac{m}{\pi r^{2}\mathcal{l}}

ΔpP×100=Δmm×100+2Δrr×100+Δll×100\frac{\Delta p}{P} \times 100 = \frac{\Delta m}{m} \times 100 + \frac{2\Delta r}{r} \times 100 + \frac{\Delta\mathcal{l}}{\mathcal{l}} \times 100q