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Question: A wire is carrying convention current down a page in a uniform magnetic field that is directed into ...

A wire is carrying convention current down a page in a uniform magnetic field that is directed into the page as shown above. What is the direction of the magnetic force on the wire

A) Into the page.
B) Out of the page.
C) To the left.
D) To the right.
E) There is no magnetic force.

Explanation

Solution

The direction of the force experienced by the current-carrying wire can be found by the use of the right-hand rule also it can be determined by the formula of the magnetic force on the current-carrying wire.

Formula used:
The formula of the force on the wire carrying current is given by,
F=I(l×B)F = I\left( {\vec l \times \vec B} \right)
Where II is the current ll is the length of wire and BB is the magnetic field.

Complete step by step answer:
In this problem, it is given that a wire with current I and length l is under the influence of a magnetic field B and we need to find the direction in which the force on the wire will be experienced.
Since the diagram says that the length is in the direction j^ - \hat j and the direction of the magnetic field is k^ - \hat k using this information we can determine the direction in which the wire carrying current will experience force.
As the formula of the force on the wire carrying current is given by,
F=I(l×B)F = I\left( {\vec l \times \vec B} \right)
Where II is the current ll is the length of wire and BB is the magnetic field.
The magnetic field is equal to B=Bk^\vec B = - B\hat k and the length of the wire is equal to l=lj^\vec l = - l\hat j, therefore, the force equals to,
F=I(l×B)\Rightarrow F = I\left( {\vec l \times \vec B} \right)
F=I(lj^×Bk^)\Rightarrow F = I\left( { - l\hat j \times - B\hat k} \right)
F=I(lj^×Bk^)\Rightarrow F = I\left( {l\hat j \times B\hat k} \right)
F=IlBi^\Rightarrow F = IlB\hat i

\therefore The force on the wire will be in the right direction. The correct option for this problem is option D.

Note:
The direction of the force applied on the current-carrying wire by an external magnetic field depends on the direction of the flow of the current in the wire and also the direction of the flow of the magnetic field.